Je zadána kvadratická rovnice: y = {{a}}x2 + {{b}}x + {{c}}
x1 =
x2 =
D =
y = {{a}}(x+{{-x1}}) (x+{{-x2}}) = {{a}}(x+{{b/2*a}})2-{{(b*b/4*a)-c}}
V = [{{-(b/2*a)}}, {{-((b*b/4*a)-c)}}]
Py = [0, {{c}}]
Px1 = [{{x1}}, 0]
Px2 = [{{x2}}, 0]
Tabulka hodnot, pro x ∈(-10; 10)
x | {{x}} |
y | {{(a*x*x+b*x+c).toFixed(2)}} |