(a+b)(b+c)(c+a) = a(b+c)(c+a) + b(b+c)(c+a) = ab(c+a) + ac(c+a) + bb(c+a) + bc(c+a) = abc + aba + acc + aca + bbc + bba + bcc + bca = abc + ab + ac + ac + bc + ba + bc + bca = abc + ab + ac + bc
Toto vyslo mne. Google keca.
(neni to a+b+c a to nabeton, ptz to by musel byt vysledok 1 uz ked napr. len a=1, ale to originalny vzorec nesplna.